Advertisements
Advertisements
प्रश्न
Plot the points P(1, 0), Q(4, 0) and S(1, 3). Find the coordinates of the point R such that PQRS is a square.
उत्तर
In point P(1, 0), y-coordinate is zero, so it lies on x-axis.
In point Q(4, 0), y-coordinate is zero so it lies on x-axis.
In point S(1, 3), both coordinates are positive, so it lies in I quadrant.
On plotting these points, we get the following graph.
Now, take a point R on the graph such that PQRS is a square.
Then, all sides will be equal i.e., PQ = QR = RS = PS.
So, abscissa of R should be equal to abscissa of Q i.e., 4 and ordinate of R should be equal to ordinate of S i.e., 3.
Hence, the coordinates of R are (4, 3).
APPEARS IN
संबंधित प्रश्न
In which quadrant or on which axis do each of the points (– 2, 4), (3, – 1), (– 1, 0), (1, 2) and (– 3, – 5) lie? Verify your answer by locating them on the Cartesian plane.
Plot the following point on the graph paper:
(−3, 2)
On a graph paper plot the points A (3, 0), B(3, 3), C(0, 3). Join A, B and B, C. What is the figure formed?
Write the equation of the line parallel to the Y-axis at a distance of 7 units from it to its left.
Find the quadrants without plotting the point on a graph sheet.
(5, 7)
Plot the following point in a graph sheet.
G(7, −4)
Find the quadrants without plotting the point on a graph sheet
(−7, 2)
Find the quadrants without plotting the point on a graph sheet.
(−8, 0)
If P(–1, 1), Q(3, –4), R(1, –1), S(–2, –3) and T(–4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant are ______.
Plot the following points and write the name of the figure obtained by joining them in order:
P(– 3, 2), Q(– 7, – 3), R(6, – 3), S(2, 2)