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Arrange the Following Polymers in Increasing Order of Their Intermolecular Forces. (I) Nylon 6, 6, Buna-s, Polythene. (Ii) Nylon 6, Neoprene, Polyvinyl Chloride. - Chemistry

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प्रश्न

Arrange the following polymers in increasing order of their intermolecular forces.

(i) Nylon 6, 6, Buna-S, Polythene.

(ii) Nylon 6, Neoprene, Polyvinyl chloride.

संक्षेप में उत्तर

उत्तर

Different types of polymers have different intermolecular forces of attraction. Elastomers or rubbers have the weakest while fibres have the strongest intermolecular forces of attraction. Plastics have intermediate intermolecular forces of attraction. Hence, the increasing order of the intermolecular forces of the given polymers is as follows:

(i) Buna − S < polythene < Nylon 6, 6

(ii) Neoprene < polyvinyl chloride < Nylon 6

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अध्याय 15: Polymers - Intext Questions [पृष्ठ ४३५]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 15 Polymers
Intext Questions | Q 6 | पृष्ठ ४३५
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