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प्रश्न
Pressure at the bottom of the sea at some particular place is 8968960 Pa. If the density of seawater is 1040 kgm3 calculate the depth of the sea. Take g = 9.8 ms−2. Neglect the pressure of the atmosphere.
उत्तर
Pressure at the bottom of the sea = P = 8968960 Pa
P = hρg
h = P/ρg
h = `8968960/(1040xx9.8)`
h = 880 m
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