Advertisements
Advertisements
प्रश्न
Prove that (4 - 5`sqrt(2)` ) is irrational.
उत्तर
Let x = 4 - 5`sqrt(2)` be a rational number.
x = 4 - 5`sqrt(2)`
⇒`x^2 = (4 - 5sqrt(2)` )2
⇒ `x^2 = 4^2 + (5sqrt(2) ) 2 – 2(4) (5 sqrt(2) )`
⇒ `x^2 = 16 + 50 – 40sqrt(2)`
⇒ `x^2 – 66 = – 40 sqrt(2)`
⇒`( 66− x^2)/40 =sqrt(2)`
Since x is a rational number, `x^2` is also a rational number.
⇒ 66 -`x^2` is a rational number
⇒ `(66− x^2)/40` is a rational number
⇒`sqrt(2)` is a rational number
But `sqrt(2)` is an irrational number, which is a contradiction.
Hence, our assumption is wrong.
Thus, (4 - 5`sqrt(2)` ) is an irrational number.
APPEARS IN
संबंधित प्रश्न
Examine, whether the following number are rational or irrational:
`sqrt7`
Examine, whether the following number are rational or irrational:
`sqrt3+sqrt5`
Find two irrational numbers lying between 0.1 and 0.12.
Prove that `1/sqrt (3)` is irrational.
Show that (5 - 2`sqrt(3)`) is irrational.
Use method of contradiction to show that √3 and √5 are irrational numbers.
Check whether the square of the following is rational or irrational:
`sqrt(2) + sqrt(3)`
Write a pair of irrational numbers whose difference is rational.
Insert a rational number and an irrational number between the following:
0.15 and 0.16
Show that x is irrational, if x2 = 27.