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Prove the following: cos(x + y).cos(x − y) = cos2y − sin2x - Mathematics and Statistics

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प्रश्न

Prove the following:

cos(x + y).cos(x − y) = cos2y − sin2x

योग

उत्तर

L.H.S. = cos(x + y) · cos (x – y)

= (cosx cosy – sinx siny) · (cosx cosy + sinx siny)

= cos2x cos2y – sin2x sin2y .....[∵ (a − b) (a + b) = a2 − b2]

= (1 – sin2x) cos2y – sin2x (1 – cos2y) ......[∵ sin2θ + cos2θ = 1]

= cos2y – sin2x cos2y – sin2x + sin2x cos2y

= cos2y – sin2x

= R.H.S.

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Trigonometric Functions of Multiple Angles
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Exercise 3.1 [पृष्ठ ३९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.1 | Q 2. (vii) | पृष्ठ ३९
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