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प्रश्न
Puneet has a Recurring Deposit Account in the Bank of Baroda and deposits Rs. 140 per month for 4 years. If he gets Rs. 8,092 on maturity, find the rate of interest given by the bank.
उत्तर
Installment per month (P) = Rs. 140
Number of months (n) = 48
Let rate of interest (r) = r% p.a.
∴ `S.I. = P xx (n(n + 1))/(2 xx 12) xx r/100`
= `140 xx (48(48 + 1))/(2xx 12) xx r/100`
= `140 xx 2352/24 xx r/100`
= Rs. (137.20)r
Maturity value = Rs. (140 × 48) + Rs. (137.20)r
Given maturity value = Rs. 8,092
Then Rs. (140 × 48) + Rs. (137.20)r = Rs. 8,092
⇒ 137.20r = Rs. 8,092 – Rs. 6,720
⇒ r = `1372/137.20` = 10%
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