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प्रश्न
Q - 34
उत्तर
Sine -1 is a root of `x^2 + px +q = 0` we have
`(-1)^2 + p(-1) + q = 0`
`=> 1 - p + q = 0`
=> -p + q = -1 ...(1)
Also 3 is root of `x^2 + px + q = 0`
`=> (3)^2 + p(3) + q = 0`
=> 9 + 3p + q = 0
=> 3p + q =-9 ...(ii)
Substracting equation 2 from 1 we get
-4p = 8
=> p = -2
`=> -(-2) + q = -1 .....[From (1)]`
=> q = -3
Hence p = -2 and q= -3
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