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प्रश्न
Show that \[2 - \sqrt{3}\] is an irrational number.
उत्तर
Let us assume that \[2 - \sqrt{3}\] is rational .Then, there exist positive co primes a and b such that
\[2 - \sqrt{3} = \frac{a}{b}\]
\[\sqrt{3} = 2 - \frac{a}{b}\]
This implies,
Hence, \[\sqrt{3}\] is irrational number.
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