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Show That: 3 √ − 125 × 216 = 3 √ − 125 × 3 √ 216 - Mathematics

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प्रश्न

Show that: \[\sqrt[3]{- 125 \times 216} = \sqrt[3]{- 125} \times \sqrt[3]{216}\]

योग

उत्तर

LHS = \[\sqrt[3]{- 125 \times 216} = \sqrt[3]{- 5 \times - 5 \times - 5 \times \left\{ 2 \times 2 \times 2 \times 3 \times 3 \times 3 \right\}} = \sqrt[3]{\left\{ - 5 \times - 5 \times - 5 \right\} \times \left\{ 2 \times 2 \times 2 \right\} \times \left\{ 3 \times 3 \times 3 \right\}} = - 5 \times 2 \times 3 = - 30\]

RHS = \[\sqrt[3]{- 125} \times \sqrt[3]{216} = \sqrt[3]{- 5 \times - 5 \times - 5} \times \sqrt[3]{\left\{ 2 \times 2 \times 2 \right\} \times \left\{ 3 \times 3 \times 3 \right\}} = - 5 \times \left( 2 \times 3 \right) = - 30\]

Because LHS is equal to RHS, the equation is true.

 
 
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अध्याय 4: Cubes and Cube Roots - Exercise 4.4 [पृष्ठ ३०]

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आरडी शर्मा Mathematics [English] Class 8
अध्याय 4 Cubes and Cube Roots
Exercise 4.4 | Q 2.3 | पृष्ठ ३०

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