Advertisements
Advertisements
प्रश्न
Show the number √7 on the number line.
उत्तर
Draw a number line as shown in the figure and mark the points O, A and B on it such that OA = AB = 1 unit. The point O represents 0 and B represents 2. At B, draw CB perpendicular on the number line such that BC = 1 unit. Join OC. Now, ∆OBC is a right angled triangle.
In ∆OBC, by Pythagoras theorem
(OC)2 = (OB)2 + (BC)2
= (2)2 + (1)2
= 4 + 1
= 5
∴ OC = √5
Taking O as centre and radius OC = √5 , draw an arc cutting the number line at D.
Clearly, OC = OD = √5
At D, draw ED perpendicular on the number line such that ED = 1 unit. Join OE. Now, ∆ODE is a right angled triangle.
In ∆ODE, by Pythagoras theorem
(OE)2 = (OD)2 + (DE)2
= (√5)2 + (1)2
= 5 + 1
= 6
∴ OE = √6
Taking O as centre and radius OE = √6 , draw an arc cutting the number line at F.
Clearly, OE = OF = √6
At F, draw GF perpendicular on the number line such that GF = 1 unit. Join OG. Now, ∆OFG is a right angled triangle.
In ∆OFG, by Pythagoras theorem
(OG)2 = (OF)2 + (FG)2
= (√6)2 + (1)2
= 6 + 1
= 7
∴ OG = √7
Taking O as centre and radius OG = √7 , draw an arc cutting the number line at H.
Clearly, OG = OH = √7
Hence, H represents √7 on the number line.
संबंधित प्रश्न
Represent these numbers on the number line
`7/4`
Show the following numbers on a number line. Draw a separate number line for each example.
(1)`3/2 , 5/2 , -3/2`
(2)`7/5 , (-2)/5 , (-4)/5`
(3) `(-5)/8 , 11/8`
(4)`13/10 , (-17)/10`
Show the following numbers on a number line. Draw a separate number line for the example.
`13/10 , (-17)/10`
Evaluate:
`1/(-15) + 5/(-12)`
Evaluate:
`(-8)/9 + -5/12`
Draw a number line and mark
`2/3, (-8)/3, 7/3, (-2)/3 and -2`
The rational number `7/(-4)` lies to the right of zero on the number line.
The rational numbers can be represented on the number line.
The rational numbers `(-12)/(-5)` and `(-7)/17` are on the opposite sides of zero on the number line.
Find a rational number exactly halfway between:
`1/15` and `1/12`
