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प्रश्न
Simplify:
`(1÷3 1/3)xx3 1/3` of `7 2/9-6`
योग
उत्तर
`(1÷3 1/3)xx3 1/3` of `7 2/9-6`
= `(1÷10/3)xx10/3` of `65/9-6`
= `(1xx3/10)xx10/3` of `65/9-6`
= `3/10xx10/3` of `65/9-6` ..........(Removing bracket)
= `3/10xx650/27-6/1` .............(Removing 'of')
= `65/9-6/1` ..............(Removing '×')
= `(65-54)/9`
= `11/9`
= `1 2/9`
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