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Simplify: 445÷35 of 5+45×310−15 - Mathematics

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प्रश्न

Simplify:

\[4\frac{4}{5} \div \frac{3}{5} \text{ of } 5 + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5}\]
योग

उत्तर

Given expression:
\[= 4\frac{4}{5} \div \frac{3}{5} \text{of} 5 + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5}\]
\[ = 4\frac{4}{5} \div \frac{3}{5} \times \frac{5}{1} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (\text{Removing 'of '})\]

\[ = \frac{24}{5} \div \frac{3}{1} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} \]
\[ = \frac{24}{5} \times \frac{1}{3} + \frac{4}{5}\times \frac{3}{10} - \frac{1}{5} (\text{Removing } '\div')\]
\[ = \frac{8}{5} + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5} (\text{Removing } ' \times ')\]
\[ = \frac{8}{5} + \frac{6}{25} - \frac{1}{5} (\text{Removing } ' \times ')\]
\[ = \frac{40 + 6 - 5}{25} = \frac{41}{25} = 1\frac{16}{25}\]

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अध्याय 6: Simplification - Exercise 6A [पृष्ठ १०७]

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आरएस अग्रवाल Mathematics [English] Class 6
अध्याय 6 Simplification
Exercise 6A | Q 7 | पृष्ठ १०७

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