Advertisements
Advertisements
प्रश्न
Simplify (ab + bc)2 − 2ab2c
उत्तर
(ab + bc)2 − 2ab2c
= (ab)2 + 2(ab)(bc) + (bc)2 − 2ab2c [(a + b)2 = a2 + 2ab + b2 ]
= a2b2 + 2ab2c + b2c2 − 2ab2c
= a2b2 + b2c2
APPEARS IN
संबंधित प्रश्न
Use a suitable identity to get the following products.
(x + 3) (x + 3)
Use a suitable identity to get the following products.
`(3a - 1/2)(3a - 1/2)`
Using a2 − b2 = (a + b) (a − b), find 512 − 492
Using a2 − b2 = (a + b) (a − b), find (1.02)2 − (0.98)2
Expand `("a"/2+"b"/3)^2`
Use the formula to multiply the following.
`("x"/5+6)("x"/5-6)`
Use a formula to multiply of (4z – 5y)(4z + 5y)
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 12x + 9
The cost of a chocolate is Rs (x + y) and Rohit bought (x + y) chocolates. Find the total amount paid by him in terms of x. If x = 10, find the amount paid by him.
If p + q = 12 and pq = 22, then find p2 + q2.
