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प्रश्न
Simplify the following:
`sum_("n" = 1)^12 "i"^"n"`
योग
उत्तर
= i1 + i2 + i3 + i4 + …. + i12
= (i – 1 – i + 1) + (i – 1 – i + 1) + (i – 1 – i + 1)
= 0
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Introduction to Complex Numbers
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