Question

${\displaystyle \sin [\frac{\pi }{3}-{\sin }^{-1}(-\frac{1}{2})]}$ is equal to:

विकल्प

• ${\displaystyle \frac{1}{2}}$

• ${\displaystyle \frac{1}{3}}$

• −1

• 1

Answer 1

1

Explanation:

${\displaystyle \sin [\frac{\pi }{3}-\left(\frac{-\pi }{6}\right)]=\sin \left(\frac{\pi }{2}\right)}$ = 1