हिंदी

Solid ammonium dichromate decomposes as: (NHA4)A2CrA2OA7⟶NA2+CrA2OA3+4HA2O If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of nitrogen formed. - Chemistry

Advertisements
Advertisements

प्रश्न

Solid ammonium dichromate decomposes as:

\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]

If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of nitrogen formed.

संख्यात्मक

उत्तर

1 mole of (NH4)2Cr2O7 contains nitrogen = 1 mole

∴ 0.25 mole of (NH4)2Cr2O7 contains nitrogen = 0.25 mole

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole concept and Stoichiometry - Miscellaneous Exercises [पृष्ठ ९६]

APPEARS IN

सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Miscellaneous Exercises | Q 24.2 | पृष्ठ ९६
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×