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प्रश्न
Solve (2x + 1)2 − (3x + 2)2 = 0
योग
उत्तर
The given equation is (2x + 1)2 (3x + 2)2 = 0
(2x + 1 + 3x + 2) [(2x + 1) – (3x + 2)] = 0
[a2 – b2 = (a + b)(a – b)]
(5x + 3)(2x + 1 – 3x – 2) = 0
(5x + 3)(– x – 1) = 0
– (5x + 3)(x + 1) = 0
5x + 3 = 0 or x + 1 = 0
x = `– 3/5` or x = – 1
∴ Solution set is `{- 1, 3/5}`
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