हिंदी

Solve: (a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0 - Mathematics

Advertisements
Advertisements

प्रश्न

Solve:

(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0

योग

उत्तर

(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0

`=>` (a + b)2x2 – 3(a + b)x + 2(a + b)x – 6 = 0

`=>` (a + b)x [(a + b)x – 3] + 2[(a + b)x – 3] = 0

`=>` [(a + b)x – 3][(a + b)x – 2] = 0

`=>` (a + b)x – 3 = 0 or (a + b)x + 2 = 0

`=> x = 3/(a + b)` or `x = (-2)/(a + b)`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Quadratic Equations - Exercise 5 (E) [पृष्ठ ६७]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic Equations
Exercise 5 (E) | Q 15 | पृष्ठ ६७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×