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प्रश्न
Solve for x using the quadratic formula. Write your answer correct to two significant figures (x -1)² – 3x + 4 = 0.
उत्तर
(x -1)² – 3x + 4 = 0
x2 + 1 - 2x - 3x + 4 = 0
x2 - 5x + 5 = 0
Comparing it with
ax2 + bx + c = 0, we get
a = 1, b = -5, c = 5
By using the formula,
x = `(-b ± sqrt(b^2 - 4ac))/(2ac)`
= `(5 ± sqrt(25 - 20))/(2)`
= `(5 ± sqrt(5))/(2)`
x = `(5 ± 2·24)/(2)`
Taking +ve sign x = `(5 + 2·24)/(2)`
x = 3·62
Taking -ve sign x = `(5 - 2·25)/(2)`
= `(2·76)/(2)`
=1·38
Thus required value are 3·62 and 1·38.
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