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प्रश्न
Solve the equation:
x4 – 14x2 + 45 = 0
उत्तर
Put t = x2
⇒ (x2)2 – 14x2 + 45 = 0
t2 – 14t + 45 = 0
t2 – 9t – 5t + 45 = 0
t(t – 9) – 5(t – 9) = 0
(t – 9)(t – 5) = 0
t – 9 = 0 or t – 5 = 0
t = 9 or t = 5
x2 = 9 or x2 = 5
x = ± 3 or y = `+- sqrt(5)`
The roots are ± 3, `+- sqrt(5)`
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