हिंदी

Solve the following equation by factorization 3(x – 2)2 = 147 - Mathematics

Advertisements
Advertisements

प्रश्न

Solve the following equation by factorization

3(x – 2)2 = 147

योग

उत्तर

3(x – 2)2 = 147
3(x2 - 4x + 4) = 147
⇒ 3x2 - 12x + 12 - 147 = 0
⇒ 3x2 - 12x - 135 = 0
⇒ x2 - 4x - 45 = 0  ...(dividing by 3)
⇒ x2 - 9x + 5x - 45 = 0
⇒ x(x - 9) + 5(x - 9) = 0
⇒ (x - 9) (x + 5) = 0
EIther x - 9 = 0,
then x = 9
or
x + 5 = 0,
then x = -5
Hence x = 9, -5.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Quadratic Equations in One Variable - Exercise 5.2

APPEARS IN

एमएल अग्रवाल Understanding ICSE Mathematics [English] Class 10
अध्याय 5 Quadratic Equations in One Variable
Exercise 5.2 | Q 7.2
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×