Advertisements
Advertisements
प्रश्न
Solve the following equation: `x - (18)/x = 6`. Give your answer correct to two x significant figures.
उत्तर
`x - (18)/x = 6`
⇒ x2 – 6x – 18 = 0
a = 1, b = -6, c = -18
x = `(-b ± sqrt(b^2 - 4ac))/(2a)`
= `(6 ± sqrt(36 + 72))/(2)`
= `(6 ± sqrt(108))/(2)`
= `(6 ± 6sqrt(3))/(2)` or `(6(1 - 1.73))/(2)`
= 3 x 2.73 or 3 x -0.73
= 8.19 or -2.19.
APPEARS IN
संबंधित प्रश्न
Check whether the following is the quadratic equation:
x3 - 4x2 - x + 1 = (x - 2)3
In the following, determine whether the given values are solutions of the given equation or not:
2x2 - x + 9 = x2 + 4x + 3, x = 2, x =3
Without solving, comment upon the nature of roots of the following equations :
`x^2 + 2sqrt3x - 9 = 0`
If x = 2/3 is a solution of the quadratic equation 7x2+mx – 3=0; Find the value of m.
Solve the following equation for x and give, in the following case, your answer correct to 2 decimal places:
x2 – 3x – 9 = 0
`x^2-4ax-b^2+4a^2=0`
`(x-4)/(x-5)+(x-6)/(x-7)=31/3,x≠5,7`
`(x/(x+1))^2-5(x/(x+1)+6=0,x≠b,a`
Solve :
`2x - 3 = sqrt(2x^2 - 2x + 21)`
If the sum of the roots of a quadratic equation is 5 and the product of the roots is also 5, then the equation is: