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प्रश्न
Solve the following quadratic equation by factorization method
`2x^2 - x + 1/8` = 0
उत्तर
`2x^2 - x + 1/8` = 0
16x2 – 8x + 1 = 0 ...(multiply by 8)
16x2 – 4x – 4x + 1
4x(4x – 1) – 1 (4x – 1) = 0
(4x – 1) (4x – 1) = 0
4x = 1, 4x = 1
x = `1/4`, x = `1/4`
The roots are `1/4` and `1/4`
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