Advertisements
Advertisements
प्रश्न
Solve the following set of simultaneous equation.
2x + y = 5; 3x - y = 5
उत्तर १
2x + y = 5
∴ y = 5 - 2x ...(I)
3x - y = 5 ...(II)
Substituting (I) in (II)
3x - y = 5
∴ 3x - (5 - 2x) = 5
∴ 3x - 5 + 2x = 5
∴ 5x = 5 + 5
5x = 10
⇒ `x = 10/5 = 2`
Putting x = 2 in (I) we have,
2 × 2 + y = 5
⇒ 4 + y = 5
⇒ y = 1
(x, y) = (2, 1)
उत्तर २
2x + y = 5 ...(1)
3x - y = 5 ...(2)
By adding equations (1) and (2),
2x + y = 5 ...(1)
3x - y = 5 ...(2)
5x = 10
∴ x = `10/5`
∴ x = 2
Substituting x = 2 in equation (1), we get
∴ 2x + y = 5
∴ 2(2) + y = 5
∴ 4 + y = 5
∴ y = 5 - 4
∴ y = 1
संबंधित प्रश्न
Form the pair of linear equations for the following problems and find their solution by substitution method.
The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is ₹ 105 and for a journey of 15 km, the charge paid is ₹ 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km?
Solve the following systems of equations:
11x + 15y + 23 = 0
7x – 2y – 20 = 0
Solve the following systems of equations:
7(y + 3) − 2(x + 2) = 14
4(y − 2) + 3(x − 3) = 2
Solve the following systems of equations:
`x/7 + y/3 = 5`
`x/2 - y/9 = 6`
Solve the following systems of equations:
`x+y = 2xy`
`(x - y)/(xy) = 6` x != 0, y != 0
Solve the following systems of equations:
`5/(x - 1) + 1/(y - 2) = 2`
Solve the following set of simultaneous equation.
x + y = 4 ; 2x - 5y = 1
Find the solution of the pair of the equation :
`3/x + 8/y = - 1; 1/x - 2/y = 2`, x, y ≠ 0
The solution of the equation 2x – y = 2 is ______
The sum of two numbers is 34. If 3 is subtracted from one number and 2 is added to another, the product of these two numbers becomes 260. Find the numbers.
