Advertisements
Advertisements
प्रश्न
Solve the inquation 8 – 2x ≥ x – 5; x ∈ N.
योग
उत्तर
8 – 2x ≥ x – 5; x ∈ N.
⇒ 8 + 5 ≥ 2x + x
⇒ 13 ≥ 3x ⇒ 3x ≤ 13
⇒ x ≤ `13/3 = 4 1/3`
x = 1, 2, 3, 4 (x ∈ N)
Solution set = {1, 2, 3, 4}
shaalaa.com
Replacement Set and Solution Set
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
If the replacement set is the set of natural numbers, solve: x - 5 < 0
If the replacement set is the set of natural numbers, solve: x + 1 ≤ 7
If the replacement set is the set of natural numbers, solve: 4x + 1 ≥ 17
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 3x + 7 < 1
Solve : 7 > 3x - 8 ; x ∈ N.
Solve : 9x - 7 ≤ 5: 28 + 4x ; x ∈ W.
Solve : `2/3"x" + 8 < 12; "x" ∈ "W"`
Solve: `-5 ("x" + 4) > 30 ; "x" ∈ "Z"`
Solve the inequation 18 – 3 (2x – 5) > 12; x ∈ W.
Solve: 4x - 5 > 10 - x, x ∈ {0, 1, 2, 3, 4, 5, 6, 7}.