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प्रश्न
Solve the quadratic equation: 16x2 + 24x + 9 = 0.
उत्तर
The given equation is 16x2 + 24x + 9 = 0
Compare the equation to ax2 + bx + c, we get
a = 16, b = 24, c = 9
Now, we know x = `(-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-24 +- sqrt((24)^2 - 4 xx 16 xx 9))/(2(16))`
= `(-24 +- sqrt(576 - 576))/32`
= `(-24 +- 0)/32`
= `(-24)/32`
= ` - 3/4`
Hence, the value of x is `- 3/4`.
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