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Solve: x(x + 1) + (x + 2)(x + 3) = 42 - Mathematics

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प्रश्न

Solve:

x(x + 1) + (x + 2)(x + 3) = 42

योग

उत्तर

x(x + 1) + (x + 2)(x + 3) = 42

`=>` x2 + x + x2 + 3x + 2x + 6 – 42 = 0

`=>` 2x2 + 6x – 36 = 0

`=>` 2x2 + 12x – 6x – 36 = 0

`=>` 2x(x + 6) – 6(x + 6) = 0

`=>` (x + 6)(2x – 6) = 0

If x + 6 = 0 or 2x – 6 = 0

Then x = – 6 or x = 3

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अध्याय 5: Quadratic Equations - Exercise 5 (E) [पृष्ठ ६७]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic Equations
Exercise 5 (E) | Q 17.1 | पृष्ठ ६७
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