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Solve: (x2 + 5x + 4)(x2 + 5x + 6) = 120 - Mathematics

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प्रश्न

Solve:

(x2 + 5x + 4)(x2 + 5x + 6) = 120

योग

उत्तर

(x2 + 5x + 4)(x2 + 5x + 6) = 120

Let x2 + 5x = y

Then (y + 4)(y + 6) = 120

`=>` y2 + 6y + 4y + 24 – 120 = 0

`=>` y2 + 10y – 96 = 0

`=>` y2 + 16y – 6y – 96 = 0

`=>` y(y + 16) – 6(y + 16) = 0

`=>` (y + 16)(y – 16) = 0

Then y = –16 or y = 6

`=>` x2 + 5x + 16 = 0 or x2 + 5x – 6 = 0

`=> x = (-5 +- sqrt((5)^2 - 4(1)(16)))/(2(1))` or `x^2 + 6x - x - 6 = 0`

`=> x = (-5 +- sqrt(-39))/2` or `x(x + 6) - 1(x + 6) = 0`

(reject) or (x + 6)(x – 1) = 0

Then x = – 6 and x = 1

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अध्याय 5: Quadratic Equations - Exercise 5 (E) [पृष्ठ ६६]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic Equations
Exercise 5 (E) | Q 11 | पृष्ठ ६६
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