Advertisements
Advertisements
प्रश्न
Solve :
x4 - 2x2 - 3 = 0
उत्तर
x4 - 2x2 - 3 = 0
⇒ x4 - 3x2 + x2 - 3 = 0
⇒ x2 (x2 - 3) +1(x2 - 3) = 0
⇒ (x2 - 3) (x2 + 1) = 0
If x2 -3 = 0 or x2 + 1 = 0
⇒ x2 = 3 or x2 + 1 = 0
⇒ x = ±`sqrt3`
APPEARS IN
संबंधित प्रश्न
Check whether the following is quadratic equation or not.
x(x + 1) + 8 = (x + 2) (x - 2)
In the following, determine whether the given values are solutions of the given equation or not:
x2 - 3x + 2 = 0, x = 2, x = -1
Solve `2x^2 - 1/2 x = 0`
Solve `sqrt(x/(x- 3)) + sqrt((x - 3)/x) = 5/2`
Solve the following equation and give your answer correct to 3 significant figures: 5x² – 3x – 4 = 0
Solve `x^2 - 11/4 x + 15/8 = 0`
Solve the following equation using the formula:
`(x - 1)/(x - 2) + (x - 3)/(x - 4) = 3 1/3`
`3((3x-1)/(2x+3))-2((2x+3)/(3x-1))=5,x≠1/3,-3/2`
Find the value of k for which the equation 3x2 – 6x + k = 0 has distinct and real roots.
Write the following quadratic equation in standard form ax2 + bx + c = 0 : x (x + 3) = 7