हिंदी

Some Liquids on Mixing Form 'Azeotropes'. What Are 'Azeotropes'? - Chemistry

Advertisements
Advertisements

प्रश्न

Some liquids on mixing form 'azeotropes'. What are 'azeotropes'?

उत्तर

Azeotropic solutions are those solutions whose boiling points remain constant. As a result, both components boil at the same temperature, regardless of difference in their respective boiling points.

Thus, binary mixtures that have the same composition in liquid and vapour phase and have constant boiling points are called azeotropes. It is not possible to separate the components of azeotropes by fractional distillation.
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2013-2014 (March) Delhi Set 2

संबंधित प्रश्न

In non-ideal solution, what type of deviation shows the formation of maximum boiling azeotropes?


Why does a solution containing non-volatile solute have higher boiling point than the pure solvent ?


What type of deviation is shown by a mixture of ethanol and acetone? Give reason.


Calculate the mass of a non-volatile solute (molar mass 40 g mol−1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.


What is meant by negative deviation from Raoult's law? Give an example. What is the sign of ∆mixH for negative deviation?


Considering the formation, breaking and strength of hydrogen bond, predict which of the following mixtures will show a positive deviation from Raoult’s law?


On the basis of information given below mark the correct option.
On adding acetone to methanol some of the hydrogen bonds between methanol molecules break.


Two liquids X and Y form an ideal solution. The mixture has a vapour pressure of 400 mm at 300 K when mixed in the molar ratio of 1 : 1 and a vapour pressure of 350 mm when mixed in the molar ratio of 1 : 2 at the same temperature. The vapour pressures of the two pure liquids X and Y respectively are ______.


The correct option for the value of vapour pressure of a solution at 45°C with benzene to octane in a molar ratio of 3 : 2 is ______

[At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]


The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution, calculate the vapour pressure of the solution.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×