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प्रश्न
Surface density of charge on a charged conducting sphere of radius R in terms of electric field intensity E at a distance r in free space is ____________.
(r > R, ε0 = permittivity of free space)
विकल्प
`ε_0 "E"("R"/"r")^2`
`ε_0 "E""R"/"r"`
`ε_0 "E"("r"/"R")^2`
`ε_0 "E""r"/"R"`
उत्तर
Surface density of charge on a charged conducting sphere of radius R in terms of electric field intensity E at a distance r in free space is `underline(ε_0 "E"("r"/"R")^2)`.
Explanation:
The electric field intensity at a distance r from the conducting sphere is
E = `1/(4πε_0) "Q"/"r"^2` ..............(i)
The surface charge density of sphere is
σ = `"Q"/(4π"R"^2)` ....................(ii)
Dividing Eqs. (ii) by (i), we get
`σ/"E" = "Q"/(4π"R"^2) xx (4πε_0"r"^2)/"Q" = ε_0("r"/"R")^2`
or σ = `ε_0 "E"("r"/"R")^2`