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प्रश्न
The 15th term of the A.P. 3, 0, –3, –6, ........ is ______.
विकल्प
– 42
39
42
– 39
MCQ
रिक्त स्थान भरें
उत्तर
The 15th term of the A.P. 3, 0, –3, –6, ........ is – 39.
Explanation:
Here a = first term = 3;
Common difference = d = 0 – 3 = – 3
We know that
Tn = a + (n – 1)d
∴ T15 = a + 14d
= 3 + 14(– 3)
= 3 – 42
= – 39
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