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प्रश्न
The 4th term from the end of the AP: –11, –8, –5, ..., 49 is ______.
विकल्प
37
40
43
58
उत्तर
The 4th term from the end of the AP: –11, –8, –5, ..., 49 is 40.
Explanation:
We know that, the nth term of an AP from the end is
an = l – (n – 1)d ...(i)
Here, l = Last term and l = 49 ...[Given]
Common difference,
d = – 8 – (– 11)
= – 8 + 11
= 3
From equation (i),
a4 = 49 – (4 – 1)3
= 49 – 9
= 40
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