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प्रश्न
The acute angle between the curve x = 2y2 and y = 2x2 at `(1/2, 1/2)` is ______.
विकल्प
`tan^-1 (4/5)`
`tan^-1 (3/4)`
`tan^-1(1)`
`tan^-1 (4/3)`
MCQ
रिक्त स्थान भरें
उत्तर
The acute angle between the curve x = 2y2 and y = 2x2 at `(1/2, 1/2)` is `tan^-1 (3/4)`.
Explanation:
x = 2y2
∴ 1 = `4y ("d"y)/("d"x)`
∴ `(("d"y)/("d"x))_(((1/2, 1/2))) = 1/2` = m1 .....(say)
and y = 2x2
∴ `("d"y)/("d"x)` = 4x
∴ `(("d"y)/("d"x))_(((1/2, 1/2)))` = 2 = m2 .....(say)
∴ Angle of intersection is tan θ = `|("m"_1 - "m"_2)/(1 + "m"_1"m"_2)|`
= `|(1/2 - 2)/(1 + (1/2)2)|`
= `3/4`
∴ θ = `tan^-1 (3/4)`
shaalaa.com
Angle between lines represented by ax2 + 2hxy + by2 = 0
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