Advertisements
Advertisements
प्रश्न
The arithmetic mean of the following data is 14. Find the value of k
x1 | 5 | 10 | 15 | 20 | 25 |
f1 | 7 | k | 8 | 4 | 5 |
उत्तर
x1 | f1 | x1f1 |
5 | 7 | 35 |
10 | k | 10k |
15 | 8 | 120 |
20 | 4 | 80 |
25 | 5 | 125 |
`sumf_1=24+k` | `sumx_1f_1=360+10k` |
We know that mean, `barx=(sumx_1f_1)/(sumf_1)`
`14=(360+10k)/(24+k)`
By using cross multiplication method,
14(24 + k) = 360 + 10k
336 + 14k = 360 + 10k
14k - 10k = 360 - 336
4k = 24
`k=24/4`
Hence, k = 6
APPEARS IN
संबंधित प्रश्न
Find the missing value of p for the following distribution whose mean is 12.58
x | 5 | 8 | 10 | 12 | P | 20 | 25 |
f | 2 | 5 | 8 | 22 | 7 | 4 | 2 |
The number of students absent in a class were recorded every day for 120 days and the information is given in the following frequency table:
No. of students absent (x) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
No. of days (f) | 1 | 4 | 10 | 50 | 34 | 15 | 4 | 2 |
Find the mean number of students absent per day.
Find the mean marks per student, using assumed-mean method:
Marks | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
Number of Students |
12 | 18 | 27 | 20 | 17 | 6 |
There are three dealers A, B and C in Maharashtra. Suppose, the trade of each of them in september 2018 was as shown in the following table.
The rate of GST on each transaction was 5%.
Read the table and answer the questions below it.
Dealer | GST collected on the sale |
GST paid at the time of purchase |
ITC | Tax paid to the Govt. |
Taxbalance with the Govt. |
A | Rs.5000 | Rs. 6000 | Rs. 5000 | Rs. 0 | Rs. 1000 |
B | Rs 5000 | Rs. 4000 | Rs. 4000 | Rs. 1000 | Rs. 0 |
C | Rs.5000 | Rs. 5000 | Rs. 5000 | Rs. 0 | Rs. 0 |
(i) How much amount did the dealer A get by sale ?
(ii) For how much amount did the dealer B buy the articles ?
(iii) How much is the balance of CGST and SGST left with the government that was paid by A ?
The arithmetic mean of 1, 2, 3, ... , n is
If the arithmetic mean of x, x + 3, x + 6, x + 9, and x + 12 is 10, the x =
If the mean of first n natural numbers is \[\frac{5n}{9}\], then n =
In X standard, there are three sections A, B and C with 25, 40 and 35 students respectively. The average marks of section A is 70%, section B is 65% and of section C is 50%. Find the average marks of the entire X standard.
Calculate the mean of the scores of 20 students in a mathematics test:
Marks | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
Number of students |
2 | 4 | 7 | 6 | 1 |
The mean of the following frequency distribution is 25. Find the value of f.
Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
Frequency | 5 | 18 | 15 | f | 6 |