Advertisements
Advertisements
प्रश्न
The arithmetic mean and mode of a data are 24 and 12 respectively, then find the median of the data.
उत्तर
Given that the arithmetic mean and mode of a data are 24 and 12 respectively. That is,
MEAN = 24
MODE = 12
We have to find median
We know that
MODE = 3 × MEDIAN - 2 × MEAN
⇒ 12 = 3 × MEDIAN - 2 × 24
⇒ 3 × MEDIAN = 12 +(2 × 24)
⇒ 3 × MEDIAN = 12+ 48
⇒ 3 × MEDIAN = 60
⇒ MEDIAN = `60/3`
⇒ MEDIAN = 20
APPEARS IN
संबंधित प्रश्न
In a mathematics test given to 15 students, the following marks (out of 100) are recorded:-
41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60
Find the mean, median and mode of this data.
Following are the weights (in kg) of 10 new born babies in a hospital on a particular day:
3.4, 3.6, 4.2, 4.5, 3.9, 4.1, 3.8, 4.5, 4.4, 3.6. Find the mean x.
Find the median of the following data (1-8)
92, 35, 67, 85, 72, 81, 56, 51, 42, 69
The weights (in kg) of 15 students are: 31, 35, 27, 29, 32, 43, 37, 41, 34, 28, 36, 44, 45, 42,30. Find the median. If the weight 44 kg is replaced by 46 kg and 27 kg by 25 kg, find the new median.
If the median of scores \[\frac{x}{2}, \frac{x}{3}, \frac{x}{4}, \frac{x}{5}\] and \[\frac{x}{6}\] (where x > 0) is 6, then find the value of \[\frac{x}{6}\] .
The mean of n observations is X. If k is added to each observation, then the new mean is
The mean of a set of seven numbers is 81. If one of the numbers is discarded, the mean of the remaining numbers is 78. The value of discarded number is
The following is the data of wages per day : 5, 4, 7, 5, 8, 8, 8, 5, 7, 9, 5, 7, 9, 10, 8
The mode of the data is
The mean of 100 observations is 50. If one of the observations which was 50 is replaced by 150, the resulting mean will be ______.
There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be –3.5. The mean of the given numbers is ______.
