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प्रश्न
The average number of phone calls per minute into the switchboard of a company between 10.00 am and 2.30 pm is 2.5. Find the probability that during one particular minute there will be no phone at all
उत्तर
The average number of phone cells per minute into the switchboard of a company is λ = 2.5
x follows poisson distribution with
P(x) = `("e"^(-lambda) lambda^x)/(x!)`
= `((2^(-2.5) (2.5)^x)/(x!))`
P(no phone at all) = P(X = 0)
= `("e"^(-2.5) (2.5)^0)/(0!)`
= `"e"^(-2.5)`
= 0.08208
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