हिंदी

The centres of the circles x2 + y2 = 1, x2 + y2 + 6x – 2y = 1 and x2 + y2 – 12x + 4y = 1 are ______. -

Advertisements
Advertisements

प्रश्न

The centres of the circles x2 + y2 = 1, x2 + y2 + 6x – 2y = 1 and x2 + y2 – 12x + 4y = 1 are ______.

विकल्प

  • same

  • collinear

  • non-collinear

  • none of these

MCQ
रिक्त स्थान भरें

उत्तर

The centres of the circles x2 + y2 = 1, x2 + y2 + 6x – 2y = 1 and x2 + y2 – 12x + 4y = 1 are collinear.

Explanation:

Centres of the circles are (0, 0), (– 3, 1) and (6, – 2) respectively.

Line passing through any two points say (0, 0) and (– 3, 1) is y = `1/3 x`

Point (6, –2) lies on it.

Hence, the centres are collinear.

shaalaa.com
Vector and Cartesian Equations of a Line
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×