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प्रश्न
The centres of the circles x2 + y2 = 1, x2 + y2 + 6x – 2y = 1 and x2 + y2 – 12x + 4y = 1 are ______.
विकल्प
same
collinear
non-collinear
none of these
MCQ
रिक्त स्थान भरें
उत्तर
The centres of the circles x2 + y2 = 1, x2 + y2 + 6x – 2y = 1 and x2 + y2 – 12x + 4y = 1 are collinear.
Explanation:
Centres of the circles are (0, 0), (– 3, 1) and (6, – 2) respectively.
Line passing through any two points say (0, 0) and (– 3, 1) is y = `1/3 x`
Point (6, –2) lies on it.
Hence, the centres are collinear.
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Vector and Cartesian Equations of a Line
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