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प्रश्न
The circular scale of a screw gauge has 50 divisions. Its spindle moves by 2 mm on the sleeve, when given four complete rotations calculate
- pitch
- least count
उत्तर
Number of circular scale divisions (C.S.D.) = 50
Distance moved by screw (spindle) on sleeve = 2 mm
Number of complete rotations given = 4
(1) Pitch = `"Distance moved by screw on sleeve"/"No. of complete rotations"`
= `(2 "mm")/4`
= 0.5 mm
(2) Pitch = 0.05 cm
Least count = `"Pitch"/"No. of circular scale divisions"`
= `0.05/50`
= 0.001 cm
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