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प्रश्न
The coagulation of 200 ML of position sol took place when 0.73 HCL was added to its without changing the volume much. The flocculation value of HCL for the colloid is.
विकल्प
0.365
36.5
100
200
MCQ
उत्तर
100
Explanation:
No. of moles of HCL = `(0.73 g)/(36.5 g "mol"^-1)` = 0.00 mol–1
No. of mill mole of HCL = 0.020
1000 = 20 milli moles
No. of mill moles of HCl required for `20/200 xx 1000` = 100.
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