Question

The correct statement with regard to \[\ce{H^+_2}\] and \[\ce{H^-_2}\] is:

विकल्प

• Both \[\ce{H^+_2}\] and \[\ce{H^-_2}\] do not exist.

• \[\ce{H^-_2}\] is more stable than \[\ce{H^+_2}\].

• \[\ce{H^+_2}\] is more stable than \[\ce{H^-_2}\].

• Both \[\ce{H^+_2}\] and \[\ce{H^-_2}\]  are equally stable.

Answer 1

`bb("H"_2^+)` is more stable than `bb("H"_2^-)`.

Explanation:

\[\ce{H^+_2}\] : σ1s¹

∴ B.O. = `1/2 (1 - 0) = 1/2`

\[\ce{H^-_2}\] : σ1s²σ*1s¹

∴ B.O. = `1/2 (2 - 1) = 1/2`

Despite the fact that the bond order of \[\ce{H^+_2}\] and \[\ce{H^-_2}\] is the same, \[\ce{H^+_2}\] is more stable than \[\ce{H^-_2}\] because one electron is present in the higher energy antibonding (σ*1s) orbital in the latter.