Advertisements
Advertisements
प्रश्न
The degree of the differential equation `1/2 ("d"^3"y")/"dx"^3 = {1 + (("d"^2"y")/"dx"^2)}^(5/3)` is ______.
विकल्प
1
15
3
9
MCQ
रिक्त स्थान भरें
उत्तर
The degree of the differential equation `1/2 ("d"^3"y")/"dx"^3 = {1 + (("d"^2"y")/"dx"^2)}^(5/3)` is 3.
Explanation:
`1/2 ("d"^3"y")/"dx"^3 = {1 + (("d"^2"y")/"dx"^2)}^(5/3)`
`=> 1/8 (("d"^3"y")/"dx"^3)^3 = {1 + (("d"^2"y")/"dx"^2)^3}^5`
Here, the highest order derivative is `("d"^3"y")/"dx"^3` with power 3.
∴ degree = 3
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
