हिंदी

The eccentricity of the hyperbola 25x2 - 9y2 = 225 is ______. -

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प्रश्न

The eccentricity of the hyperbola 25x2 - 9y2 = 225 is ______.

विकल्प

  • `sqrt34/3`

  • 4

  • `sqrt34`

  • `sqrt34/5`

MCQ
रिक्त स्थान भरें

उत्तर

The eccentricity of the hyperbola 25x2 - 9y2 = 225 is `underline(sqrt34/3)`.

Explanation:

We have equation of hyperbola 25x2 - 9y2 = 225

`=> x^2/9 - "y"^2/25 = 1`

On comparing with `x^2/"a"^2 - "y"^2/"b"^2 = 1`, we get

a2 - 9, b2 = 25

∴ Eccentricity, e = `sqrt(1 + "b"^2/"a"^2)`

`= sqrt(1 + 25/9)`

`= sqrt34/3`

shaalaa.com
Conic Sections - Hyperbola
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