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प्रश्न
The eccentricity of the hyperbola 25x2 - 9y2 = 225 is ______.
विकल्प
`sqrt34/3`
4
`sqrt34`
`sqrt34/5`
MCQ
रिक्त स्थान भरें
उत्तर
The eccentricity of the hyperbola 25x2 - 9y2 = 225 is `underline(sqrt34/3)`.
Explanation:
We have equation of hyperbola 25x2 - 9y2 = 225
`=> x^2/9 - "y"^2/25 = 1`
On comparing with `x^2/"a"^2 - "y"^2/"b"^2 = 1`, we get
a2 - 9, b2 = 25
∴ Eccentricity, e = `sqrt(1 + "b"^2/"a"^2)`
`= sqrt(1 + 25/9)`
`= sqrt34/3`
shaalaa.com
Conic Sections - Hyperbola
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