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प्रश्न
The edge length of the unit cell of a body-centred cubic (bcc) crystal is 352 pm. Calculate the radius of the atom.
टिप्पणी लिखिए
उत्तर
For bcc crystal,
`sqrt(3)a = 4r`
a = 352 pm
∴ `sqrt(3) xx 352 = 4 xx r`
`r = sqrt(3) xx 352/4`
= `1.732 xx 8.8 "pm" = 152.4 "pm"`
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States of Matters: Structure and Properties Solid State - Concept of Radius, Edge Length and Nearest Neighbour Distance
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