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प्रश्न
The electron affinity of an element X is greater than that of element Y.
How is the oxidising power of X likely to compare with that of Y?
उत्तर
X has more oxidising power than Y.
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संबंधित प्रश्न
Draw an electron dot diagram to show the formation of each of the following compounds:
Methane
[H = 1, C = 6, Mg = 12, Cl = 17]
Element X is a metal with a valency 2, Y is 3 non- metal with a valency 3.
1) Write an equation to show how Y from an ion.
2) If Y is a diatomic gas, write an equation for the direct combination of X and Y to form a compound.
Explain the following:
Halogens have a high electron affinity.
Arrange the elements of group 17 and group 1 according to the given conditions.
Increasing electron affinity
A, B, C are three elements in which B is an inert gas other than helium.With this information complete the following table.
| Element | Atomic number | No. of electrons in the valence shell | Group to which the element belongs |
| A | Z - 1 | ||
| B | Z | ||
| C | Z + 1 |
Also, explain the following : Electron affinity of B is Zero.
Fill in the blank
Noble gases have ______ electron affinity.
Explain
Halogens have high electron affinity.
The following questions refer to the Periodic Table.
Which of the elements has the greatest electron affinity among the halogens?
Arrange the following as per instruction given in the bracket.
Cl, F, Br, I (increasing electron affinity)
The electron affinity of an element X is greater than that of element Y.
How is the electronegativity of X likely to compare with that of Y?
