Advertisements
Advertisements
प्रश्न
The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.
उत्तर
Given the empirical formula of the compound is C2H5.
Vapour density is = 29 .
Empirical formula mass of the compound = 29
As, molecular mass = 2 x vapour density = 2 x 29 = 58
So, molecular mass of the compound =58
Molecular formula = n x Empirical formula
Now, n = Molecular mass/ Empirical formula mass = 58/ 29 =2
Molecular formula = 2 x (C2H5 ) = C4H10
So, molecular formula of compound is = C4H10
APPEARS IN
संबंधित प्रश्न
A compound of X and Y has the empirical formula XY2. Its vapor density is equal to its empirical formula weight. Determine its molecular formula.
A compound made up of two elements X and Y has an empirical formula X2Y. If the atomic weight of X is 10 and that of Y is 5 and the compound ha a vapor density 25, find its molecular formula.
Explain the terms empirical formula and molecular formula.
Give example of compound whose:
Empirical formula is different from the molecular formula.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
Calculate the percentage of water of crystallization in CuSO4. 5H2O
(H = 1, O = 16, S = 32, Cu = 64)
0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.
Give the empirical formula of C6H18O3
A compound is formed by 24 g of X and 64 g of oxygen. If the atomic mass of X = 12 and O = 16, calculate the simplest formula of the compound.
Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.
