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प्रश्न
The equation of a circle with centre at (1, 0) and circumference 10π units is ______.
विकल्प
x2 + y2 – 2x + 24 = 0
x2 + y2 – x – 25 = 0
x2 + y2 – 2x – 24 = 0
x2 + y2 + 2x + 24 = 0
MCQ
रिक्त स्थान भरें
उत्तर
The equation of a circle with centre at (1, 0) and circumference 10π units is x2 + y2 – 2x – 24 = 0.
Explanation:
Centre (1, 0), circumference = 10π ...(given)
∴ 2πr = 10π `\implies` r = 5
So, equation of circle is (x – 1)2 + (y – 0)2 = 25
`\implies` x2 + y2 – 2x – 24 = 0
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Different Forms of Equation of a Circle
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