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प्रश्न
The equation of the line touching both the parabolas y2 = x and x2 = y is ______.
विकल्प
4x + 4y + 1 = 0
4x + 4y – 1 = 0
x + y + 1 = 0
4x – 4y + 1 = 0
MCQ
रिक्त स्थान भरें
उत्तर
The equation of the line touching both the parabolas y2 = x and x2 = y is 4x + 4y + 1 = 0.
Explanation:
Let equation of tangent of y2 = x is y = `mx + a/m` where a = `1/4`
y = `mx + 1/(4m)` ...(i)
This is also touches x2 = y ...(ii)
∴ From (1) and (2)
x2 = `mx + 1/(4m)`
⇒ `x^2 - mx - 1/(4m)` = 0
D = 0
`m^2 + 4. 1/(4m)` = 0
m3 = –1
m = –1
∴ Required equation y = `-x - 1/4`
⇒ 4y = –4x – 1
⇒ 4x + 4y + 1 = 0
shaalaa.com
Conic Sections - Parabola
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