हिंदी

The expression (cosA+cosBsinA-sinB)n+(sinA+sinBcosA-cosB)n = ______. -

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प्रश्न

The expression `((cos A + cos B)/(sin A - sin B))^n + ((sin A + sin B)/(cos A - cos B))^n` = ______.

विकल्प

  • `2 cot^n ((A - B)/2)` if n is even

  • 0 if n is even

  • `2 cot^n ((A - B)/2)` if n is odd

  • 3 if n is odd

MCQ
रिक्त स्थान भरें

उत्तर

The expression `((cos A + cos B)/(sin A - sin B))^n + ((sin A + sin B)/(cos A - cos B))^n` = `underlinebb(2 cot^n ((A - B)/2) "if n is even")`.

Explanation:

The given expression

= `((2 cos((A + B)/2) cos((A - B)/2))/(2 cos((A + B)/2) sin((A - B)/2)))^n + ((2 sin((A + B)/2) cos((A - B)/2))/(2 sin((A + B)/2) sin((B - A)/2)))^n`

= `cot^n ((A - B)/2) + (-1)^n cot^n ((A - B)/2)`

= `{{:(2 cot^n ((A - B)/2),",", "If n is even"),(0,",", "if n is odd"):}`

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