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The faces of a die bear numbers 0, 1, 2, 3, 4, 5. If the die is rolled twice, then find the probability that the product of digits on the upper face is zero. - Algebra

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प्रश्न

The faces of a die bear numbers 0, 1, 2, 3, 4, 5. If the die is rolled twice, then find the probability that the product of digits on the upper face is zero.

योग

उत्तर

Sample space,

S = {(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5),

(1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5),

(2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5),

(3, 0), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5),

(4, 0), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5),

(5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5)}

∴ n(S) = 36

Let A be the event that the product of digits on the upper face is zero.

∴ A = {(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (1, 0), (2, 0), (3, 0), (4, 0), (5, 0)}

∴ n(A) = 11

∴ P(A) = `("n"("A"))/("n"("S"))`

∴ P(A) = `11/36`

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